Question

A 50 N force is applied to an object of mass 5 kg, as shown in the figure.If the coefficient of friction between the object and the horizontal plane is 0.5, what is the acceleration of the object, in m/s2?​

Answer 1

Ответ:

50/0.5=100 /2=50

Объяснение:

Answer 2

To find the acceleration of the object, we need to apply Newton's second law of motion.

According to Newton's second law, the acceleration of an object is equal to the net force acting on it divided by its mass.

Given: Force applied (F) = 50 N Mass (m) = 5 kg Coefficient of friction (μ) = 0.5

First, let's calculate the force of friction (Ff) using the formula Ff = μ * N, where N is the normal force.

The normal force (N) can be calculated as N = m * g, where g is the acceleration due to gravity (approximately 9.8 m/s²).

N = 5 kg * 9.8 m/s² N = 49 N

Ff = 0.5 * 49 N Ff = 24.5 N

Now, we can calculate the net force (Fnet) acting on the object. Since the applied force is greater than the force of friction, the net force can be found by subtracting the force of friction from the applied force.

Fnet = F - Ff Fnet = 50 N - 24.5 N Fnet = 25.5 N

Finally, we can calculate the acceleration (a) using the formula a = Fnet / m.

a = 25.5 N / 5 kg a = 5.1 m/s²

Therefore, the acceleration of the object is 5.1 m/s².