Question

Какая максимальная масса льда ті, находящегося при температуре плавления, может расплавиться в воде массой т2 = 10 кг с температурой, равной t = 50 °С? Удельная теплота плавления льда равна А= 340 кДж/кг, удельная теплоёмкость воды равна с = 4200 Дж/(кг-°С.) Обменом энергии с окружающей средой пренебречь. Ответ выразить в кг, округлив до десятых.​

Answer 1

Ответ:

6,2

Объяснение:

zxc

Answer 2

Calculation of the Maximum Mass of Ice that can Melt in Water

To calculate the maximum mass of ice that can melt in water, we need to consider the heat transfer between the ice and water. The heat transfer equation can be expressed as:

Q = m1 * c1 * ΔT1 = m2 * L + m2 * c2 * ΔT2

Where: - Q is the heat transferred - m1 is the mass of ice - c1 is the specific heat capacity of ice - ΔT1 is the change in temperature of the ice - m2 is the mass of water - L is the latent heat of fusion of ice - c2 is the specific heat capacity of water - ΔT2 is the change in temperature of the water

We are given the following values: - m2 = 10 kg (mass of water) - t = 50 °C (temperature of water) - A = 340 kJ/kg (latent heat of fusion of ice) - c = 4200 J/(kg-°C) (specific heat capacity of water)

To find the maximum mass of ice that can melt, we need to determine the change in temperature of the ice (ΔT1). Since the ice is at its melting point, the change in temperature of the ice will be 0 °C.

Substituting the given values into the heat transfer equation, we can solve for m1:

m1 * c1 * 0 = m2 * A + m2 * c2 * ΔT2

Simplifying the equation:

m1 = (m2 * A) / (c2 * ΔT2)

Since the change in temperature of the water is given as t = 50 °C, we can substitute this value into the equation:

m1 = (m2 * A) / (c2 * t)

Now we can calculate the maximum mass of ice that can melt in water.

m1 = (10 kg * 340 kJ/kg) / (4200 J/(kg-°C) * 50 °C)

Calculating the result:

m1 ≈ 0.81 kg

Therefore, the maximum mass of ice that can melt in water with a mass of 10 kg and a temperature of 50 °C is approximately 0.81 kg.