Question

ДАЮ 50 БАЛЛОВ Сколько керосина надо сжечь, чтобы 5 кг льда, взятого при - 40 градусов превратить в пар в цинковом ведре массой 500г?

Answer 1

Ответ:

8,04г

10°С

1,55кг

Объяснение:

очолклвргвшулутуиоввщщулвоаитаос

Answer 2

Calculating the Amount of Kerosene Needed to Convert Ice to Steam

To calculate the amount of kerosene needed to convert 5 kg of ice at -40 degrees Celsius to steam in a 500g zinc bucket, we can use the specific heat capacity of ice and steam, as well as the latent heat of fusion and vaporization.

1. Amount of Heat Required to Convert Ice to Water at 0°C: - The specific heat capacity of ice is 2.09 J/g°C. - The latent heat of fusion for ice is 334 J/g. - The formula to calculate the heat required to convert ice to water at 0°C is: \[ Q = m \times c \times \Delta T + m \times L_f \] where: - \( Q \) = heat required - \( m \) = mass of ice - \( c \) = specific heat capacity of ice - \( \Delta T \) = change in temperature - \( L_f \) = latent heat of fusion

2. Amount of Heat Required to Convert Water to Steam at 100°C: - The specific heat capacity of water is 4.18 J/g°C. - The latent heat of vaporization for water is 2260 J/g. - The formula to calculate the heat required to convert water to steam at 100°C is: \[ Q = m \times c \times \Delta T + m \times L_v \] where: - \( Q \) = heat required - \( m \) = mass of water - \( c \) = specific heat capacity of water - \( \Delta T \) = change in temperature - \( L_v \) = latent heat of vaporization

3. Calculation: - First, we need to calculate the heat required to convert 5 kg of ice at -40°C to water at 0°C, and then from water at 0°C to steam at 100°C. - Finally, we can convert the heat to the amount of kerosene needed using its energy content.

Let's proceed with the calculations.