Question

Завдання 6. Котигорошко підкинув вертикально вгору свою булаву, надавши їй швидкості 20 м/с. На яку максимальну над поверхнею Землі висоту підніметься булава? Опором повітря знехтуйте.​

Answer 1

H=(V²-Vo²)/(-2g) торможение.
Конечная скорость=0.
h=20²/20=20 м.
Это ответ.

Answer 2

To determine the maximum height the baton will reach when thrown vertically upwards by Kotigoroshko, we can use the equations of motion. Assuming no air resistance, we can use the following equation:

v^2 = u^2 + 2as

Where: - v is the final velocity (which will be zero at the maximum height) - u is the initial velocity (20 m/s in this case) - a is the acceleration (which is equal to the acceleration due to gravity, approximately 9.8 m/s^2) - s is the displacement (the maximum height we want to find)

Rearranging the equation, we have:

s = (v^2 - u^2) / (2a)

Since the final velocity is zero at the maximum height, we can simplify the equation to:

s = u^2 / (2a)

Substituting the given values, we have:

s = (20^2) / (2 * 9.8) = 204.08 meters

Therefore, the baton will reach a maximum height of approximately 204.08 meters above the surface of the Earth when thrown vertically upwards by Kotigoroshko, neglecting air resistance.