Question

Ядро,летевшее горизонтально со скоростью 20м/с разорвалось на 2 осколка массами 5 и 10кг.Скорость меньшего осколка 90м/c и направлена вертикально вверх. Определите модуль и направление скорости большего осколка.

Answer 1

Закон сохранения импульса!

(m1+m2)V1=m1V1'+m2V2'

(10+5)*20=5*90+10*V2'

300=450+10V2'

10V2'=300-450=-150

V2'=-15 м/с

по модулю / 15 / м/с

Знак "-" показывает направление снараяда => больший осколок полетел в противоположную сторону, т.е. вниз 

Answer 2

Given Information

A projectile traveling horizontally at a speed of 20 m/s breaks into two fragments with masses of 5 kg and 10 kg. The velocity of the smaller fragment is 90 m/s and directed vertically upward.

Solution

To determine the magnitude and direction of the velocity of the larger fragment, we can use the principles of conservation of momentum.

The total momentum before the explosion is equal to the total momentum after the explosion. This can be expressed as:

m1u1 = m1v1 + m2v2

Where: - m1 and m2 are the masses of the fragments - u1 is the initial velocity of the projectile - v1 and v2 are the final velocities of the fragments

Calculation

Given: - Initial velocity of the projectile, u1 = 20 m/s - Mass of the smaller fragment, m1 = 5 kg - Mass of the larger fragment, m2 = 10 kg - Velocity of the smaller fragment, v1 = 90 m/s

Using the conservation of momentum equation, we can solve for the velocity of the larger fragment, v2:

m1u1 = m1v1 + m2v2

20 * 5 = 5 * 90 + 10 * v2

100 = 450 + 10v2

10v2 = -350

v2 = -35 m/s

Answer

The magnitude of the velocity of the larger fragment is 35 m/s. The negative sign indicates that the direction of the velocity is opposite to the initial direction of the projectile.

Therefore, the direction of the velocity of the larger fragment is opposite to the initial direction of the projectile.