Question

Плечи важеля,який перебуває в рівновазі, доривнюють 10см и 30см. менша сила що дие на важиль,доривнюе 4H.Знайти більшу силу

Answer 1

Ответ:

12н

Объяснение:

30*4=120

120/10=12н

Answer 2

The Problem

The question asks us to find the greater force acting on a lever that is in equilibrium, where the lever arm lengths are 10cm and 30cm, and the smaller force acting on the lever is 4H.

A lever is a rigid object that is used to multiply force. It works based on the principle of moments, where the clockwise and counter-clockwise torques must be equal when the lever is in equilibrium.

The lever in this question has two forces acting on it - a smaller force of 4H acting on one end with a lever arm of 10cm, and an unknown greater force acting on the other end with a lever arm of 30cm. Since these two torques must be equal for equilibrium:

`Torque of smaller force = Torque of greater force`

`4H * 10cm = Greater Force * 30cm`

`40H = Greater Force * 30`

`Greater Force = 40H / 30`

`Greater Force = 13H`

Therefore, the greater force acting on the lever is 13H.