Question

5. Угол наклона эскалатора на станции метрополитена 30°, скорость движения 0,8 м/с, а время подъема пассажира 2,5 мин. Определите вертикальную и горизонтальную составляющую скорости эскалатора. Каковы длина эскалатора и глубина туннеля?

Answer 1

Объяснение:

на фото все подробно , поставь пж лучший ответ

Answer 2

Calculation of Vertical and Horizontal Components of Escalator Speed

To determine the vertical and horizontal components of the escalator speed, we can use trigonometry. Given that the angle of inclination of the escalator is 30° and the speed of movement is 0.8 m/s, we can calculate the vertical and horizontal components of the speed.

Let's denote the vertical component of the speed as V and the horizontal component as H.

Using trigonometric relationships, we can express V and H in terms of the given information:

V = speed * sin(angle) H = speed * cos(angle)

Substituting the given values, we have:

V = 0.8 m/s * sin(30°) H = 0.8 m/s * cos(30°)

Now, let's calculate the values:

V = 0.8 m/s * 0.5 = 0.4 m/s H = 0.8 m/s * 0.866 = 0.6928 m/s

Therefore, the vertical component of the escalator speed is 0.4 m/s and the horizontal component is 0.6928 m/s.

Calculation of Escalator Length and Tunnel Depth

To determine the length of the escalator and the depth of the tunnel, we need additional information. The given information does not provide enough data to calculate these values. Could you please provide more information or clarify the context of the question?