Question

Автомобіль швидкості з місця розганяється до 36 км/год на відстані 40 м. Знайти час руху на цій ділянці та прискорення автомобіля.​

Answer 1

Ответ:

Объяснение:

V = 36 км/год = 10 м/с

Vo = 0

S =  40 м

t = ?

a = ?

a = (V - Vo) / t = V / t

a = 2*S / t^2

приравняем относительно а

V / t = 2*S / t^2

V = 2*S / t

отсюда время

t = 2*S / V = 2*40 / 10 = 8 c

ускорение

а = V / t = 40 / 8 = 5 м/с^2

Answer 2

Calculation of Time and Acceleration

To find the time it takes for the car to travel a distance of 40 meters and the acceleration of the car, we can use the equations of motion.

The equation that relates distance, initial velocity, time, and acceleration is:

distance = initial velocity * time + (1/2) * acceleration * time^2

In this case, the initial velocity is 0 km/h (since the car starts from rest), the distance is 40 meters, and we need to find the time and acceleration.

Let's solve for time first:

40 = 0 * t + (1/2) * a * t^2

Since the initial velocity is 0, the equation simplifies to:

40 = (1/2) * a * t^2

Now, let's solve for acceleration:

a = (2 * 40) / t^2

We also know that the car reaches a speed of 36 km/h (or 10 m/s) after accelerating. We can use this information to find the time it takes for the car to reach this speed.

10 = 0 + a * t

Solving for time:

t = 10 / a

Now we have two equations with two unknowns (a and t). We can solve them simultaneously to find the values.

Let's substitute the value of t from the second equation into the first equation:

40 = (1/2) * a * (10 / a)^2

Simplifying:

40 = (1/2) * a * (100 / a^2)

Simplifying further:

40 = 50 / a

Solving for a:

a = 50 / 40

Simplifying:

a = 1.25 m/s^2

Now, let's substitute the value of a back into the second equation to find t:

t = 10 / (1.25)

Simplifying:

t = 8 seconds

Therefore, the car takes 8 seconds to travel a distance of 40 meters and the acceleration of the car is 1.25 m/s^2.