Question

Контейнер з цеглою масою 750 кг піднімають із швидкістю 20 см/с. Яка робота здійснюється за 20 с підйому? Яку роботу за цей час здійснює сила тяжіння?

Answer 1

Ответ:

W = F × h,

У цьому випадку, висота підйому дорівнює 20 см = 0,2 м, тому:

W = F × h = 750 кг × 9,8 Н/кг × 0,2 м = 1470 Дж.

Отже, робота, здійснена силою тяжіння, дорівнює 1470 Дж.

Answer 2

Calculation of Work Done

To calculate the work done in lifting a container with a mass of 750 kg at a speed of 20 cm/s for 20 s, we can use the formula:

Work = Force × Distance

In this case, the force involved is the force of gravity acting on the container, which is equal to its weight. The weight of an object can be calculated using the formula:

Weight = Mass × Acceleration due to gravity

The acceleration due to gravity on Earth is approximately 9.8 m/s². Therefore, the weight of the container is:

Weight = 750 kg × 9.8 m/s²

To convert the lifting speed from cm/s to m/s, we divide by 100:

Lifting Speed = 20 cm/s ÷ 100 = 0.2 m/s

Now, we can calculate the distance traveled by the container during the 20 s of lifting:

Distance = Lifting Speed × Time

Distance = 0.2 m/s × 20 s

Finally, we can calculate the work done:

Work = Weight × Distance

Work = (750 kg × 9.8 m/s²) × (0.2 m/s × 20 s)

Let's calculate the values to find the work done.