Question

4. а) Капля дождя массой 5 мг движется со скоростью 2 м/с на высоте 3 км. Вычислите потенциальную энергию, которой обладает капля? ​

Answer 1

Дано:
m = 5мг = 0,000005 кг
v = 2 м/с
h = 3000 м
Найти:
Еп-?
Eп = mgh
Eп = 0,000005 · 10 · 3000 = 0,15 Дж
Ответит: 0,15 Дж

Answer 2

Calculation of Potential Energy

To calculate the potential energy of the raindrop, we can use the formula:

Potential Energy = mass * gravitational acceleration * height

Given: - Mass of the raindrop = 5 mg = 5 * 10^-6 kg - Gravitational acceleration = 9.8 m/s^2 - Height = 3 km = 3000 m

Using the given values, we can calculate the potential energy of the raindrop as follows:

Potential Energy = (5 * 10^-6 kg) * (9.8 m/s^2) * (3000 m)

Calculating this expression gives us the potential energy of the raindrop.

Let's calculate it step by step:

Step 1: Convert the mass of the raindrop from milligrams to kilograms: - 5 mg = 5 * 10^-6 kg

Step 2: Substitute the values into the formula: - Potential Energy = (5 * 10^-6 kg) * (9.8 m/s^2) * (3000 m)

Step 3: Calculate the expression: - Potential Energy = 0.000049 J

Therefore, the potential energy of the raindrop is approximately 0.000049 Joules.