Question

Индеец выпускает стрелу из лука вертикально вверх с начальной скоростью 25 м/с. Какой максимальной высоты она достигнет через время 2,5 с? ( g=10м/с") ​

Answer 1

Ответ: 31,25м

Объяснение:

Дано:

Vo=25м/с

t=2,5с

g=10м/c²

------------

h-?

h=Vo*t-gt²/2=25*2,5-10*2,5²/2=31,25м

Answer 2

Calculation of Maximum Height Reached by an Arrow Shot Vertically Upwards

To calculate the maximum height reached by an arrow shot vertically upwards, we can use the equations of motion. The key equation we will use is:

v^2 = u^2 - 2as

Where: - v is the final velocity (which is 0 when the arrow reaches its maximum height) - u is the initial velocity (given as 25 m/s) - a is the acceleration due to gravity (given as 10 m/s^2) - s is the displacement (which is the maximum height we want to find)

We can rearrange the equation to solve for s:

s = (u^2)/(2a)

Substituting the given values:

s = (25^2)/(2*10) = 31.25 meters

Therefore, the maximum height reached by the arrow is 31.25 meters.

Please note that this calculation assumes no air resistance and neglects other factors that may affect the arrow's trajectory.