Question

С какой силой давит вода на иллюминатор батискафа на глубине 1,5 км если площадь иллюминатора 0,16 м

Answer 1

Ответ:

Ответ:F=2472000Па

Объяснение:F = ρсв * g * h * S = 1030 *10*1500*0.16=2472000 Па

Answer 2

Water Pressure on the Submarine Window

The pressure exerted by water on a submarine window at a depth of 1.5 km can be calculated using the formula for pressure:

Pressure = Force / Area

To find the force exerted by the water, we need to calculate the weight of the water column above the window. The weight of the water column is given by the formula:

Weight = Density x Volume x Gravity

The density of seawater is approximately 1025 kg/m³, and the volume of the water column can be calculated by multiplying the depth by the area of the window. The acceleration due to gravity is approximately 9.8 m/s².

Let's calculate the pressure exerted by the water on the submarine window.

Given: - Depth: 1.5 km (or 1500 m) - Area of the window: 0.16 m²

First, let's calculate the weight of the water column above the window:

Weight = Density x Volume x Gravity

Volume = Depth x Area Volume = 1500 m x 0.16 m² = 240 m³

Weight = 1025 kg/m³ x 240 m³ x 9.8 m/s² = 2,372,800 N

Now, let's calculate the pressure:

Pressure = Force / Area

Pressure = 2,372,800 N / 0.16 m² = 14,830,000 N/m²

Therefore, the water exerts a pressure of approximately 14,830,000 N/m² on the submarine window at a depth of 1.5 km.

Please note that the above calculations are based on the assumption that the water pressure is evenly distributed across the window and that the window is strong enough to withstand the pressure.