Question

двигун внутрішнього згоряння автомобіля має потужність 40кВт та ККД 25 °/°. Яку кількість бензину він витрачає за 2 години​

Answer 1

Ответ:

20%=0,20=1/5 часть.

Значит только пятая часть энергии сгоревшего бензина пойдет на работу двигателя.

A=P*t=36700 Br*3600 c=1,32*10³Дж

КПД=А/Q

Q=A/0,2=1,32*10³*5=6,6*10³ДЖ

Q=q*m

m=Q/q=6,6*108/(46*10®)=660*10/ (46*10°)=14,35 кг. Это ответ.

Если у Вас 15 кг, значит другое немного значение q.

Answer 2

Calculation of Fuel Consumption

To calculate the amount of gasoline consumed by an internal combustion engine in a given time period, we need to know the power output of the engine and its efficiency, also known as the thermal efficiency or the efficiency of the engine.

In this case, the engine has a power output of 40 kW and an efficiency of 25%.

To calculate the fuel consumption, we can use the following formula:

Fuel Consumption = Power Output / (Efficiency * Energy Content of Fuel)

The energy content of gasoline is typically around 34.2 MJ/L.

Let's calculate the fuel consumption for a 2-hour period:

Fuel Consumption = (40 kW) / (0.25 * 34.2 MJ/L) * (2 hours)

Using this formula, we can calculate the fuel consumption.

Calculation:

Fuel Consumption = (40 kW) / (0.25 * 34.2 MJ/L) * (2 hours)

Fuel Consumption = 0.235 L

Therefore, the engine would consume approximately 0.235 liters of gasoline in a 2-hour period.

Please note that this calculation is an approximation and may vary depending on various factors such as driving conditions, engine efficiency, and other variables.