Question

определите мощность, развиваемую двигателем трактора, который при скорости движения 18км.ч преодолевает силу сопротивления 40кН​

Answer 1

Ответ:

определите мощность развиваемую двигателем трактора который при скорости 18км/ч преодолевает силу сопротивления равную 40кН

V=18 км/ч=5 м/с F=40 000 Н N - ?

N=V*F=5*40 000=200 000 Вт= 200 кВт

N=200 кВт

Answer 2

Calculation of Engine Power

To determine the power developed by the tractor's engine, we need to use the formula:

Power (P) = Force (F) x Velocity (V)

Given: - Force of resistance (F) = 40 kN - Velocity (V) = 18 km/h

First, we need to convert the velocity from km/h to m/s, as the SI unit for velocity is meters per second (m/s).

1 km/h is equal to 0.2778 m/s. Therefore, the velocity (V) can be calculated as follows:

V = 18 km/h x 0.2778 m/s per km/h

Now, we can substitute the values into the formula to calculate the power (P):

P = F x V

P = 40 kN x V

Let's calculate the velocity (V) and the power (P) using the given values.

Velocity (V): 18 km/h x 0.2778 m/s per km/h = 5 m/s

Power (P): P = 40 kN x 5 m/s

To calculate the power, we need to convert kilonewtons (kN) to newtons (N). 1 kN is equal to 1000 N.

P = 40,000 N x 5 m/s

Now, we can calculate the power:

P = 200,000 watts (W)

Therefore, the engine of the tractor develops a power of 200,000 watts (W) when overcoming a resistance force of 40 kN at a speed of 18 km/h.