Question

конденсатор заряжен до разности потенциалов 120 В. накопленый заряд равен 5 мкКл. Какой энергией обладает заряженный конденсатор. Определите емкость конденсатора.

Answer 1

Ответ:

C $\approx 0,42 \cdot 10^{-7}$ Ф.

W = $3024 \cdot 10^{-7}$ Дж.

Объяснение:

Дано:

U = 120 В

$q = 5 \cdot 10^{-6}$ Кл

Найти:

W - ?

C - ?

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Решение:

$\boxed{C = \dfrac{q}{U} }$ - емкость конденсатора

C = $5 \cdot 10^{-6}$ Кл / 120 В $\approx 0,42 \cdot 10^{-7}$ Ф

$W = \dfrac{CU^{2}}{2}$

W = $0,42 \cdot 10^{-7}$ Ф * (120 В)² /2 = $0,42 \cdot 10^{-7}$ Ф * 7 200 В² = $3024 \cdot 10^{-7}$ Дж

Ответ: C $\approx 0,42 \cdot 10^{-7}$ Ф. W = $3024 \cdot 10^{-7}$ Дж.

Answer 2

Charged Capacitor Energy and Capacitance Calculation

A capacitor charged to a potential difference of 120 V with a stored charge of 5 µC possesses energy. The energy stored in a capacitor can be calculated using the formula:

E = (1/2) * C * V^2

Where: - E is the energy stored in the capacitor - C is the capacitance of the capacitor - V is the potential difference across the capacitor

Using the given potential difference of 120 V and the stored charge of 5 µC, we can calculate the energy stored in the capacitor.

First, let's calculate the energy:

E = (1/2) * C * V^2 5 µC = (1/2) * C * (120 V)^2 5 µC = (1/2) * C * 14400 5 µC = 7200 * C C = 5 µC / 7200 C ≈ 0.6944 µF

So, the energy stored in the charged capacitor is not available from the provided search results. However, we can calculate the capacitance of the capacitor, which is approximately 0.6944 µF based on the given information and the formula for capacitance.

Therefore, the energy possessed by the charged capacitor is not available from the search results, but the capacitance of the capacitor is approximately 0.6944 µF.