Question

Карусель на дитячому майданчику містить сидіння, розташовані на відстані 2 метри від осі обертання та робить 5 обертів за 50 секунд. Знайдіть період обертання каруселі, та лінійну швидкість дитини, що катається на ній.

Answer 1

Ответ:

1. оцени мой ответ лучшим

Объяснение:

Дано:

R=2m

N=5

t=50сек

найти n v ω?

$n=\frac{N}{t} =\frac{5}{50}=0.1$

омега=2n$\pi$=$2\pi *0.1=\frac{2\pi }{5} =1.8 рад\с$

v=R*омега=3,6 м/с

Answer 2

Calculation of Carousel's Rotation Period and Linear Speed

To find the rotation period of the carousel, we can use the formula:

Rotation Period (T) = Time Taken for n Rotations / Number of Rotations (n)

In this case, the carousel makes 5 rotations in 50 seconds. Therefore, the rotation period can be calculated as:

T = 50 seconds / 5 rotations = 10 seconds per rotation

The rotation period of the carousel is 10 seconds.

To find the linear speed of a child riding on the carousel, we need to know the distance traveled by the child in one rotation. Since the seats are located 2 meters away from the axis of rotation, the circumference of the circle formed by the seats can be calculated using the formula:

Circumference (C) = 2 * π * Radius

In this case, the radius is 2 meters. Therefore, the circumference can be calculated as:

C = 2 * π * 2 meters = 4π meters

The linear speed of the child can be calculated using the formula:

Linear Speed (v) = Distance Traveled / Time Taken

In one rotation, the child travels the circumference of the circle. Therefore, the distance traveled in one rotation is 4π meters. Using the rotation period of 10 seconds, the linear speed can be calculated as:

v = (4π meters) / (10 seconds) = (2π/5) meters per second

The linear speed of the child riding on the carousel is (2π/5) meters per second.

Please note that the above calculations assume that the carousel is a perfect circle and that the child is riding on the outer edge of the seats.