Question

железная плита размером a=4 м, b=0,3 м, c=0,25 м, погружена в воду на половину своего объёма. Какова архимедова сила, действующая на неё?​

Answer 1

Ответ:

1,5

Объяснение:

Дано:

a = 4 м

b = 0,3 м

c = 0,25 м

р = 1000 кг/м³

Найти: F арх - ?

Решение:

F арх = pgV погружённой части тела (далее - пчт)

Т.к. V пчт = 0,5V по условию задачи, а V = abc, то

V пчт = 0,5abc

F арх = 0,5pgabc

F арх = 0,5 × 1000 кг/м³ × 10 Н/кг × 4 м × 0,3 м × 0,25 м = 1500 Н = 1,5Дано:

a = 4 м

b = 0,3 м

c = 0,25 м

р = 1000 кг/м³

Найти: F арх - ?

Решение:

F арх = pgV погружённой части тела (далее - пчт)

Т.к. V пчт = 0,5V по условию задачи, а V = abc, то

V пчт = 0,5abc

F арх = 0,5pgabc

F арх = 0,5 × 1000 кг/м³ × 10 Н/кг × 4 м × 0,3 м × 0,25 м = 1500 Н = 1,5

Answer 2

Ответ:

1500

Объяснение:

Fa=pgv F=((4×0.3×0.25):2)×10×1000=1500

Answer 3

Calculation of Archimedes' Force

To calculate the Archimedes' force acting on the iron plate submerged in water, we need to consider the buoyant force. The buoyant force is equal to the weight of the fluid displaced by the submerged object.

The weight of the fluid displaced can be calculated using the formula:

Weight of fluid displaced = density of fluid x volume of fluid displaced x acceleration due to gravity

In this case, the fluid is water, which has a density of approximately 1000 kg/m^3. The volume of fluid displaced is half the volume of the iron plate, which can be calculated using the formula:

Volume of fluid displaced = (a x b x c) / 2

where: - a = 4 m (length of the iron plate) - b = 0.3 m (width of the iron plate) - c = 0.25 m (height of the iron plate)

Now we can calculate the volume of fluid displaced:

Volume of fluid displaced = (4 m x 0.3 m x 0.25 m) / 2 = 0.15 m^3

Substituting the values into the formula for the weight of fluid displaced:

Weight of fluid displaced = 1000 kg/m^3 x 0.15 m^3 x 9.8 m/s^2 = 1470 N

Therefore, the Archimedes' force acting on the iron plate is 1470 N.