Question

Два шарика с зарядами +2 нКл и -3 нКл находятся на расстоянии 0,03 м а) вычислите, с какой силой притягиваются шарики в керосине. ____________________________________________________________________________________________________________________________________________[2] б) рассчитайте во сколько раз изменится сила взаимодействия между зарядами при увеличении расстояния в 2 раза ________________________________________________________________________________________________________________________________________________[

Answer 1

Ответ:

а) 33,3 мкКл

б) при увеличении расстояния в 2 раза, сила взаимодействия между зарядами уменьшится в 4 раза, так как расстояние обратно пропорционально силе Кулона

Объяснение:

Answer 2

Calculation of the force of attraction between the charged spheres in kerosene:

To calculate the force of attraction between the two charged spheres, we can use Coulomb's Law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Given: - Charge of the first sphere (q1) = 2 nC - Charge of the second sphere (q2) = -3 nC - Distance between the spheres (r) = 0.03 m

Using Coulomb's Law, the formula to calculate the force of attraction (F) between the spheres is:

F = (k * |q1 * q2|) / r^2

Where: - k is the electrostatic constant, approximately equal to 9 x 10^9 Nm^2/C^2 - |q1 * q2| is the product of the magnitudes of the charges - r^2 is the square of the distance between the spheres

Let's calculate the force of attraction between the spheres:

F = (9 x 10^9 Nm^2/C^2 * |2 nC * -3 nC|) / (0.03 m)^2

Using the given values, we can calculate the force of attraction.

[[2]]

Calculation of the change in the force of interaction when the distance is doubled:

To calculate the change in the force of interaction between the charges when the distance is doubled, we can use the inverse square relationship between force and distance.

Given: - Initial distance between the charges (r1) = 0.03 m - New distance between the charges (r2) = 2 * r1 = 0.06 m

The force of interaction (F) between the charges is inversely proportional to the square of the distance (r).

F1 / F2 = (r2 / r1)^2

Let's calculate the change in the force of interaction when the distance is doubled:

F1 / F2 = (0.06 m / 0.03 m)^2

Using the given values, we can calculate the change in the force of interaction.

[[2]]