Question

Пуля массой 100 г, имея скорость 800 м / с пробивает доску толщиной 10 см. Скорость пули уменьшается до 400 м / с Найти силу сопротивления со стороны доски Куля масою 100 г, Маючи швидкість 800 м / с пробиває дошку товщиною 10 см. Швидкість кулі зменшується до 400 м / с Знайти силу опору з боку дошки

Answer 1

Ответ:

НАВЕРНОЕ ТОЧНО НЕ ЗНАЮ

Объяснение:

Переведём граммы в килограммы : 10г = 0.01кг

Энегрия пули : K = m* V^2/2

была K = 0,01кг*800м/с*800/2 =3200 дж

стала K = 0,01кг*400м/с*400/2 =800 дж

Работа, затраченная на проход доски = 3200-800 = 2400дж

A = F*S, следовательно

F = A:S = 2400:0.08 = 30000 H

Ответ: 30000 Н!

Answer 2

Calculation of Resistance Force

To find the resistance force exerted by the board on the bullet, we can use the principle of conservation of momentum. The initial momentum of the bullet is equal to its final momentum after passing through the board.

The momentum of an object is given by the product of its mass and velocity. Therefore, we can calculate the initial momentum of the bullet using its initial mass and velocity, and the final momentum using its final mass and velocity.

Given: - Mass of the bullet (m) = 100 g = 0.1 kg - Initial velocity of the bullet (v1) = 800 m/s - Final velocity of the bullet (v2) = 400 m/s

The initial momentum (p1) of the bullet is given by: p1 = m * v1

The final momentum (p2) of the bullet is given by: p2 = m * v2

Since momentum is conserved, we can equate p1 and p2: m * v1 = m * v2

Simplifying the equation, we can cancel out the mass (m) on both sides: v1 = v2

Therefore, the resistance force exerted by the board on the bullet is zero. This means that the board does not exert any force on the bullet as it passes through.

Please note that the information provided is based on the given data and assumptions.