Question

Латунный сосуд при нагревании увеличился в объёме на n=0,6 %. На сколько градусов Цельсия был нагрет сосуд, если температурный коэффициент линейного расширения латуни α=2⋅10−51∘C? Округлите ответ до целого числа.

Answer 1

Ответ:

100 градусов цельсия

Объяснение:

0.006%/1=t*3a

считаем:

t=0.006%/3a=100

Answer 2

#### Calculation of the Temperature Increase To calculate the temperature increase of the brass vessel, we can use the formula for linear expansion: **ΔL = α * L * ΔT** Where: - ΔL is the change in length (or volume in this case) - α is the coefficient of linear expansion - L is the original length (or volume) - ΔT is the change in temperature In this case, we are given that the vessel increased in volume by 0.6% (n = 0.6%). We need to find the change in temperature (ΔT) that caused this volume increase. The coefficient of linear expansion for brass (α) is given as 2 * 10^(-5) 1/°C. Let's solve for ΔT: **0.6% = α * L * ΔT** Since the volume change is proportional to the length change, we can rewrite the equation as: **0.6% = α * ΔT** Now we can solve for ΔT: **ΔT = (0.6% / α)** Substituting the given value for α: **ΔT = (0.6% / 2 * 10^(-5) 1/°C)** Using the given value of ΔT, we can calculate the temperature increase. #### Calculation: To calculate the temperature increase, we need to substitute the given values into the equation: **ΔT = (0.6% / 2 * 10^(-5) 1/°C)** Calculating this expression gives us: **ΔT ≈ 0.03 / 2 * 10^(-5) °C** Simplifying further: **ΔT ≈ 1500 °C** Therefore, the brass vessel was heated by approximately 1500 degrees Celsius. Please note that this calculation assumes a linear relationship between temperature and volume change, which may not be perfectly accurate in practice.