Question

C=100пФ L=250мкГн v-?

Answer 1

Так здесь ничего трудного нету, приступим
С=100ПФ=
$10 {}^{ - 10}$
Фарад
L=250 мкГн=
$25 \times 10 {}^{ - 5}$
Генри
По формуле Томсона
Т=2пи
$\sqrt{lc}$
Т=1/v
Возводим в квадрат и ставим вместо периода 1/v
1/v^2=4pi^2LC
C=1/v^2*4pi^2*L
Это вся формула, и по этой формуле найдите С

Answer 2

To calculate the resonant frequency (v) of a series RLC circuit with given values of capacitance (C) and inductance (L), you can use the following formula:

v = 1 / (2 * π * √(L * C))

Where:

• v is the resonant frequency in Hertz (Hz).
• π is the mathematical constant Pi, approximately equal to 3.14159.
• L is the inductance in Henrys (H).
• C is the capacitance in Farads (F).

Given your values: C = 100 picofarads (pF), which is equivalent to 100 * 10^(-12) F. L = 250 microhenrys (μH), which is equivalent to 250 * 10^(-6) H.

Let's plug these values into the formula:

v = 1 / (2 * π * √(250 * 10^(-6) H * 100 * 10^(-12) F))

v = 1 / (2 * π * √(2.5 * 10^(-5) H * 10^(-10) F))

v = 1 / (2 * π * √(2.5 * 10^(-15) H*F))

v = 1 / (2 * π * √(2.5 * 10^(-15)))

v ≈ 1 / (2 * 3.14159 * 5 * 10^(-8))

v ≈ 1 / (3.14159 * 5 * 10^(-8))

v ≈ 6366.2 * 10^7 Hz

v ≈ 63.662 MHz

So, the resonant frequency (v) of the series RLC circuit with a capacitance of 100 pF and inductance of 250 μH is approximately 63.662 MHz.