Question

V0= 20 м/с t1=2c V=16м/с а-?

Answer 1

Ускорение идет в противоположную сторону, так как оно меньше нуля

Answer 2

To find the acceleration (a), you can use the following kinematic equation:

$V = V_0 + at$

Where:

• $V$ is the final velocity (16 m/s).
• $V_0$ is the initial velocity (20 m/s).
• $a$ is the acceleration (which we want to find).
• $t$ is the time (2 seconds).

Now, plug in the values:

$16 \, \text{m/s} = 20 \, \text{m/s} + a \cdot 2 \, \text{s}$

Now, solve for $a$:

$16 \, \text{m/s} - 20 \, \text{m/s} = 2a$ $-4 \, \text{m/s} = 2a$

Now, divide both sides by 2 to isolate $a$:

$\frac{-4 \, \text{m/s}}{2} = a$ $-2 \, \text{m/s}^2 = a$

So, the acceleration is $-2 \, \text{m/s}^2$. The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.