Question

M1-200 m2=30 t1=40 t2=10

Answer 1

Дано: 

m1=200 г

t1=40°C

m2=30 г

t2=10°C

Найти t-?

Решение:

При смешивании теплой и холодной, теплая вода отдает теплоту равную Q1, а холодная вода поглащает теплоту равную Q2. Т.к.  энергия никуда не девается Q1=Q2. 

Q1=c*m1(t1-t);

Q2=c*m2(t-t2).

c*m(t1-t)=c*m(t-t2);

m1*(t1-t)=m2*(t-t2);

Выражаем отсюда t : 

t=(m1*t1+m2*t2)/(m1+m2)=(200*40+30*10)/(200+30)=36,1°С

Answer 2

It appears that you have provided some variables without specifying what you would like to do with them. The variables you've given are:

• M1 = 200
• m2 = 30
• t1 = 40
• t2 = 10

To provide a meaningful response, please let me know what you want to calculate or what specific question you have related to these variables. For example, are you looking for the gravitational force between two masses, or is there some other calculation or concept you need help with? Feel free to clarify, and I'll be happy to assist you further!