Question

СРОЧНО ДАМ 35 БАЛЛОВ Автобус ехал от остановки до остановки со скоростью 60 км/ч. На всех остановочных пунктах он находился одинаковое количество времени. Продолжительность движения автобуса между остановками приведена в таблице. Средняя скорость за время движения на четырех участках Ucp = 50 км/ч. Первый участок - Продолжительность 20 мин Второй участок - Продолжительность 5 мин Третий участок - Продолжительность 10 мин Четвертый участок - Продолжительность 10 минОпределите минимальный путь между двумя соседними остановками. Ответ выразите в км. Варианты: 0.3 км, 5 км, 3000 км.Определите весь путь, который преодолел автобус на четырех участках. Ответ выразите в км.Определите продолжиельнось одной остановки. Ответ выразите в минутах.

Answer 1

Ответ:

5 км

45 км

3 мин

Объяснение:

скорость 60 км/ч, 1 км/мин, мин время 5 мин = 5 км.

4 участка - 20+5+10+10 = 45 мин = 45 км

средняя скорость 50 км/ч, весь путь 54 мин. - 45 мин на движение между остановками = 9 мин на три остановки = 3 мин остановка

Answer 2

Calculation of Minimum Distance between Two Adjacent Stops

To determine the minimum distance between two adjacent stops, we need to calculate the total distance traveled by the bus on each of the four segments and then sum them up.

Given: - Average speed during the four segments (Ucp) = 50 km/h - Duration of the first segment = 20 minutes - Duration of the second segment = 5 minutes - Duration of the third segment = 10 minutes - Duration of the fourth segment = 10 minutes

To calculate the distance traveled on each segment, we can use the formula:

Distance = Speed x Time

Let's calculate the distance traveled on each segment:

1. Distance on the first segment: - Speed = 50 km/h - Time = 20 minutes = 20/60 hours = 1/3 hours - Distance = 50 km/h x 1/3 hours = 50/3 km

2. Distance on the second segment: - Speed = 50 km/h - Time = 5 minutes = 5/60 hours = 1/12 hours - Distance = 50 km/h x 1/12 hours = 25/6 km

3. Distance on the third segment: - Speed = 50 km/h - Time = 10 minutes = 10/60 hours = 1/6 hours - Distance = 50 km/h x 1/6 hours = 25/3 km

4. Distance on the fourth segment: - Speed = 50 km/h - Time = 10 minutes = 10/60 hours = 1/6 hours - Distance = 50 km/h x 1/6 hours = 25/3 km

Now, let's calculate the total distance traveled by summing up the distances on each segment:

Total distance = Distance on the first segment + Distance on the second segment + Distance on the third segment + Distance on the fourth segment

Total distance = (50/3) km + (25/6) km + (25/3) km + (25/3) km

Total distance = (50/3 + 25/6 + 25/3 + 25/3) km

Total distance = (100/6 + 25/6 + 50/6 + 50/6) km

Total distance = 225/6 km

Simplifying the fraction, we get:

Total distance = 37.5 km

Therefore, the total distance traveled by the bus on the four segments is 37.5 km.

To determine the duration of one stop, we need to subtract the total duration of the four segments from the total duration of the trip.

Total duration of the trip = Duration of the first segment + Duration of the second segment + Duration of the third segment + Duration of the fourth segment

Total duration of the trip = 20 minutes + 5 minutes + 10 minutes + 10 minutes

Total duration of the trip = 45 minutes

Since the bus spends an equal amount of time at each stop, the duration of one stop can be calculated by dividing the total duration of the trip by the number of stops.

Number of stops = 4 (since there are four segments)

Duration of one stop = Total duration of the trip / Number of stops

Duration of one stop = 45 minutes / 4

Duration of one stop = 11.25 minutes

Therefore, the duration of one stop is approximately 11.25 minutes.

To summarize: - The minimum distance between two adjacent stops is 37.5 km. - The duration of one stop is approximately 11.25 minutes.