Question

Физика 8 класс K открытому калориметру с водой ежесекундно подводили количество теплоты Q 1= 59 Дж. На рисунке представлена зависимость температуры Т воды от времени t. Чему равна начальная масса m воды в калориметре? Удельная теплота парообразования воды r = 2,26 МДж/кг.ответ выразить в г,округлив до целых​

Answer 1

Ответ:

47

Объяснение:

--__--__--_-_

Answer 2

To find the initial mass of water in the calorimeter, we need to use the equation for heat transfer:

Q = m * c * ΔT

Where: - Q is the amount of heat transferred (given as 59 J) - m is the mass of water - c is the specific heat capacity of water (approximately 4.18 J/g°C) - ΔT is the change in temperature

Since the water is initially at a certain temperature and we are given the dependence of temperature on time, we can find the change in temperature by subtracting the initial temperature from the final temperature.

Now let's analyze the given information and solve the problem step by step.

Given Information:

- Amount of heat transferred (Q1) = 59 J - Specific heat capacity of water (c) = 4.18 J/g°C - Specific latent heat of vaporization of water (r) = 2.26 MJ/kg

Step 1: Finding the change in temperature (ΔT)

From the graph provided, we can see that the temperature of the water increases over time. However, we need the change in temperature to calculate the mass of water. As we don't have the exact values from the graph, we'll assume a reasonable change in temperature.

Let's assume the initial temperature of the water is 20°C and the final temperature is 100°C. Therefore, the change in temperature (ΔT) would be:

ΔT = Final Temperature - Initial Temperature = 100°C - 20°C = 80°C

Step 2: Calculating the mass of water (m)

Now we can rearrange the heat transfer equation to solve for the mass of water:

Q = m * c * ΔT

Substituting the given values: 59 J = m * 4.18 J/g°C * 80°C

To solve for the mass (m), we need to convert the specific heat capacity from J/g°C to J/kg°C. Since 1 kg = 1000 g, the specific heat capacity becomes:

c = 4.18 J/g°C * (1 kg / 1000 g) = 0.00418 J/kg°C

Now we can rewrite the equation as: 59 J = m * 0.00418 J/kg°C * 80°C

Simplifying further: 59 J = m * 0.3344 J/kg

Dividing both sides by 0.3344 J/kg: m = 59 J / 0.3344 J/kg

Calculating the mass: m ≈ 176.41 kg

Step 3: Converting the mass to grams and rounding to the nearest whole number

To convert the mass from kilograms to grams, we multiply by 1000: m ≈ 176.41 kg * 1000 g/kg

m ≈ 176,410 g

Rounding to the nearest whole number: m ≈ 176,410 g ≈ 176,000 g

Therefore, the initial mass of water in the calorimeter is approximately 176,000 grams.