Question

тело брошено горизонтально с высоты 20м с начальной скоростью 20 м/с. Сопротивлением воздуха можно пренебречь. Сколько времени длится полёт тела до падения на землю? Чему равна дальность полёта? ​

Answer 1

Ответ:

H= gt^2/ 2

t^2= 2H/ g= 2*20/ 10= 4

t= 2c

L= V0* t= 20*2= 40

Объяснение:

Answer 2

Problem Analysis

We are given the following information: - The body is thrown horizontally from a height of 20m with an initial velocity of 20 m/s. - Air resistance can be neglected.

We need to find: 1. The time of flight of the body before it hits the ground. 2. The horizontal distance covered by the body during its flight.

To solve this problem, we can use the equations of motion for horizontal and vertical motion.

Solution

1. Time of Flight: - Since the body is thrown horizontally, its initial vertical velocity is zero. - The only force acting on the body is gravity, which causes it to accelerate vertically downwards. - We can use the equation of motion for vertical motion: h = ut + (1/2)gt^2, where h is the initial height, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight. - Substituting the given values, we have: 20 = 0*t + (1/2)*9.8*t^2. - Simplifying the equation, we get: 4.9t^2 = 20. - Solving for t, we find: t = sqrt(20/4.9) ≈ 2.02 seconds.

2. Horizontal Distance: - Since there is no horizontal force acting on the body, its horizontal velocity remains constant throughout the flight. - We can use the equation of motion for horizontal motion: s = ut, where s is the horizontal distance covered, u is the initial horizontal velocity, and t is the time of flight. - Substituting the given values, we have: s = 20 * 2.02 ≈ 40.4 meters.

Answer

Therefore, the time of flight of the body before it hits the ground is approximately 2.02 seconds, and the horizontal distance covered by the body during its flight is approximately 40.4 meters.

Please let me know if you need any further clarification.