Question

велосипедист съезжает с горки двигаясь прямолинейно и равноускоренно за время спуска скорость велосипедиста увеличилась на 15 м/c. Ускорение велосипедиста 0.5 м/c Сколько времени длится спуск?

Answer 1

Ответ:

10m/c вроде правильно я могу фото скинуть как решается

Answer 2

Problem Analysis

We are given that a cyclist is descending a hill in a straight line with constant acceleration. During the descent, the cyclist's speed increases by 15 m/s, and the acceleration is 0.5 m/s². We need to determine the duration of the descent.

Solution

To solve this problem, we can use the equations of motion for uniformly accelerated motion. The relevant equation is:

v = u + at

where: - v is the final velocity - u is the initial velocity - a is the acceleration - t is the time

In this case, the cyclist's initial velocity is 0 m/s because they start from rest. The final velocity is the sum of the initial velocity and the change in velocity:

v = u + Δv

Substituting the given values:

v = 0 + 15 m/s = 15 m/s

Now we can rearrange the equation to solve for time:

t = (v - u) / a

Substituting the values:

t = (15 m/s - 0 m/s) / 0.5 m/s² = 30 s

Therefore, the descent lasts for 30 seconds.

Answer

The descent of the cyclist lasts for 30 seconds.