Question

Количество теплоты, отданное нагревателем тепловому двигателю — 28 кДж. От теплового двигателя холодильнику передаётся 20 кДж. Найди работу, совершённую тепловым двигателем. Ответ: кДж. помогте пжпжпжп ссроччно даю 30 балов

Answer 1

$A = Q_1 - Q_2 = 28 - 20 = 8$

Answer 2

To find the work done by the heat engine, we can use the first law of thermodynamics, which states that the work done by a system is equal to the difference between the heat added to the system and the heat rejected by the system.

In this case, the heat added to the heat engine is 28 kJ, and the heat rejected to the refrigerator is 20 kJ. Therefore, the work done by the heat engine can be calculated as:

Work done = Heat added - Heat rejected

Work done = 28 kJ - 20 kJ

Work done = 8 kJ

Therefore, the work done by the heat engine is 8 kJ.

Please let me know if there's anything else I can help you with!