Question

Металлический самородок неправильной формы осторожно окунули в наполненную трёхлитровую банку с керосином. Когда самородок вынули, банка оказалась наполовину пустой. Определите плотность металла, если масса самородка 11 11 кг 100 100 г. Плотность керосина 0,8 0 , 8 г/см3 3 . Ответ дайте в г/см3 3 , округлив до десятых. Помогите пожалуйста

Answer 1

Ответ:

Объяснение:

7.4

Answer 2

Calculation of Density

To determine the density of the metal, we can use the formula:

Density = Mass / Volume

Given that the mass of the metal nugget is 11 kg and the mass of the kerosene in the jar is 100 g, we need to calculate the volume of the metal nugget and the volume of the kerosene.

Calculation of Volume

The volume of the kerosene can be calculated using its density, which is given as 0.8 g/cm³. Since the mass of the kerosene is 100 g, we can use the formula:

Volume = Mass / Density

Substituting the values, we get:

Volume of Kerosene = 100 g / 0.8 g/cm³

Calculating this, we find that the volume of the kerosene is 125 cm³.

To find the volume of the metal nugget, we can subtract the volume of the kerosene from the total volume of the jar, which is 3000 cm³ (since it is a 3-liter jar).

Volume of Metal Nugget = Total Volume of Jar - Volume of Kerosene

Substituting the values, we get:

Volume of Metal Nugget = 3000 cm³ - 125 cm³

Calculating this, we find that the volume of the metal nugget is 2875 cm³.

Calculation of Density

Now that we have the mass and volume of the metal nugget, we can calculate its density using the formula:

Density = Mass / Volume

Substituting the values, we get:

Density of Metal = 11 kg / 2875 cm³

Calculating this, we find that the density of the metal is approximately 0.0038 g/cm³.

Therefore, the density of the metal is approximately 0.0038 g/cm³.

Please note that the density is rounded to the nearest tenth.