
Цепь состоит из последовательно включенных резисторов R1 = 10 Ом, R2=20 Ом. Найти общее
сопротивление, общий ток, напряжение на каждом сопротивлении, проводимость цепи, если напряжение, приложенное к цепи равно 30 В. Найти количество теплоты, которое выделилось на сопротивлении R2 за 1 сутки.

Ответы на вопрос

Ответ:
Объяснение:
R1=10 Ом R2=20 Ом U=30 B t=86400 c
Ro=? Io=? Ro=? U1=? U2=? j=? Q2=?
===
Ro=R1+R2=10+20=30 Ом
Io=U/Ro=30/30=1 A
U1=Io*R1=1*10=10 B
U2=Io*R2=1*20=20 B
j=1/Ro=1/30≈0.033 Ом⁻¹
Q2=Io²*R2*t=1²*20*86400=1728*10³ Дж
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Calculation of Total Resistance:
To find the total resistance of the circuit, we need to calculate the equivalent resistance of the series combination of resistors R1 and R2. In a series circuit, the total resistance is the sum of the individual resistances.The formula to calculate the total resistance in a series circuit is:
Total Resistance (R_total) = R1 + R2
Substituting the given values:
R1 = 10 Ω R2 = 20 Ω
R_total = 10 Ω + 20 Ω = 30 Ω
Calculation of Total Current:
To find the total current flowing through the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R).The formula to calculate the total current in a circuit is:
Total Current (I_total) = Voltage (V) / Total Resistance (R_total)
Substituting the given values:
Voltage (V) = 30 V Total Resistance (R_total) = 30 Ω
I_total = 30 V / 30 Ω = 1 A
Therefore, the total current flowing through the circuit is 1 A.
Calculation of Voltage across Each Resistor:
In a series circuit, the voltage across each resistor is the same as the total voltage applied to the circuit.Therefore, the voltage across each resistor in this circuit is 30 V.
Calculation of Conductance of the Circuit:
Conductance (G) is the reciprocal of resistance (R) and is a measure of how easily current can flow through a circuit.The formula to calculate conductance is:
Conductance (G) = 1 / Total Resistance (R_total)
Substituting the given value:
Total Resistance (R_total) = 30 Ω
G = 1 / 30 Ω = 0.033 S Therefore, the conductance of the circuit is 0.033 S.
Calculation of Heat Dissipated on Resistor R2 in 1 Day:
To calculate the heat dissipated on resistor R2, we need to use the formula for electrical power (P) dissipated on a resistor, which is given by:Power (P) = (Current (I))^2 * Resistance (R)
Substituting the given values:
Current (I) = 1 A Resistance (R) = 20 Ω
Power (P) = (1 A)^2 * 20 Ω = 20 W
The power dissipated on resistor R2 is 20 W.
To calculate the heat dissipated in 1 day, we need to multiply the power by the time:
Heat Dissipated = Power * Time
Assuming 1 day is equal to 24 hours:
Heat Dissipated = 20 W * 24 hours = 480 Wh
Therefore, the amount of heat dissipated on resistor R2 in 1 day is 480 Wh.
Please note that the above calculations assume ideal conditions and do not take into account factors such as temperature variations or changes in resistance due to heating.


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