Question

При растяжении пружины на 34,2 см в ней возникает сила упругости, равная 47 Н. Определите потенциальную энергию этой пружины при растяжении ее на 5,6 см. (ответ в Дж, округлить до тысячных)

Answer 1

Ответ: 0,215Дж

Объяснение:

Дано:

х=0,342 м

Fупр=47 Н

х2=0,056 м

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Еп-?

Fупр=kx

k=47/0,342=137,427 Н/м

Ер=k(x2)²/2=137,427*0,056²/2=0,215 Дж

Answer 2

Calculation of Potential Energy

To calculate the potential energy of a spring, we can use the formula:

Potential Energy = (1/2) * k * x^2

Where: - k is the spring constant, which represents the stiffness of the spring. - x is the displacement of the spring from its equilibrium position.

In this case, we are given that the spring is stretched by 34.2 cm (0.342 m) and the force of elasticity is 47 N. We need to determine the potential energy when the spring is stretched by 5.6 cm (0.056 m).

To find the spring constant (k), we can rearrange the formula for force:

Force = k * x

Solving for k:

k = Force / x

Using the given values:

k = 47 N / 0.342 m

Calculating k:

k ≈ 137.426 N/m Now, we can calculate the potential energy when the spring is stretched by 5.6 cm:

Potential Energy = (1/2) * k * x^2

Substituting the values:

Potential Energy = (1/2) * 137.426 N/m * (0.056 m)^2

Calculating the potential energy:

Potential Energy ≈ 0.217 J

Therefore, the potential energy of the spring when stretched by 5.6 cm is approximately 0.217 J.

Note: The answer has been rounded to the thousandth decimal place.