Question

Задание № 11 Мальчик аккуратно бросает кота вертикально вверх. Когда кот достигает максимальной высоты своего полёта, мальчик бросает вверх второго кота, с той же скоростью и с того же места, что и первый. В результате коты радостно встречаются на высоте H = 2,1 м от места броска. Какой максимальной высоты H­0, считая от места броска, достигал в своём полёте первый кот? Ответ дайте в см. Сопротивление воздуха не учитывать. Коты не пострадали.​

Answer 1

Опять котов обижают !!!  ))

Двух котов смело можно заменить одним .

Второй кот летит от места броска до места встречи столько же времени, сколько первый кот летит от места встречи до Земли.

И это же время равно половине общего времени падения первого кота с искомой высоты.

Высота подъема определяется по формуле

h=g*T^2/2

Имеем

g*(T/2)^2/2 = H0 - H  

H0 = g*T^2/2

1,25*T^2 = 5*T^2 - 2,1

3,75*T^2= 2,1

H0 = 5*T^2 = 2,1*5/3,75 = 2,8 м

Answer 2

Problem Analysis

In this problem, a boy throws two cats vertically upwards. The cats meet each other at a height of 2.1 meters above the throwing point. We need to determine the maximum height reached by the first cat.

Solution

Let's assume that the maximum height reached by the first cat is H₀.

When the first cat reaches its maximum height, it starts to fall back down. At this point, the second cat is thrown upwards with the same initial speed and from the same position as the first cat. Since both cats meet at a height of 2.1 meters, the second cat must have traveled the same vertical distance as the first cat fell.

Therefore, the maximum height reached by the first cat, H₀, is equal to the sum of the height at which the cats meet (2.1 meters) and the distance the first cat falls before meeting the second cat.

To find the distance the first cat falls, we can use the equation of motion for vertical motion:

Δy = V₀t + (1/2)gt²

Where: - Δy is the vertical distance traveled - V₀ is the initial vertical velocity - t is the time taken - g is the acceleration due to gravity (approximately 9.8 m/s²)

In this case, the initial vertical velocity of the first cat is zero when it reaches its maximum height. The time taken for the first cat to reach its maximum height can be calculated using the equation:

V = V₀ + gt

Where: - V is the final vertical velocity (zero at maximum height)

Using these equations, we can calculate the maximum height reached by the first cat.

Calculation

Let's calculate the maximum height reached by the first cat:

1. Calculate the time taken for the first cat to reach its maximum height: - V = V₀ + gt - 0 = V₀ + gt - t = -V₀ / g

2. Calculate the distance the first cat falls before meeting the second cat: - Δy = V₀t + (1/2)gt² - Δy = 0 + (1/2)g(-V₀ / g)² - Δy = (1/2)(-V₀² / g)

3. Calculate the maximum height reached by the first cat: - H₀ = 2.1 + (1/2)(-V₀² / g)

Answer

The maximum height reached by the first cat, H₀, can be calculated using the equation: H₀ = 2.1 + (1/2)(-V₀² / g).

Please note that the given problem does not provide the initial velocity of the cats or any other relevant information required to calculate the maximum height accurately. If you have any additional information, please provide it so that we can assist you further.