Question

Два тела массой по 5 кг каждое двигались на встречу друг другу со скоростями равными 50 и 35 м/с. Какова скорость второго тела после соударения, если скорость первого стала равна 7,5 м/с?

Answer 1

50-7,5=42,5м/с / зменшилась швидкіст 1
42,5-(50-35)=27,5
35-27,5=7,5 м/с - швидкісь 2

Answer 2

Calculation of the velocity of the second body after collision

To calculate the velocity of the second body after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum of the first body before the collision is (mass of the first body) x (velocity of the first body), and the momentum of the second body before the collision is (mass of the second body) x (velocity of the second body).

After the collision, the velocity of the first body becomes 7.5 m/s. Let's denote the velocity of the second body after the collision as v2.

Using the principle of conservation of momentum, we can write the following equation:

(mass of the first body) x (velocity of the first body) + (mass of the second body) x (velocity of the second body) = (mass of the first body) x (velocity of the first body after collision) + (mass of the second body) x (velocity of the second body after collision)

Substituting the given values:

(5 kg) x (50 m/s) + (5 kg) x (35 m/s) = (5 kg) x (7.5 m/s) + (5 kg) x (v2)

Simplifying the equation:

250 kg·m/s + 175 kg·m/s = 37.5 kg·m/s + 5 kg·v2

425 kg·m/s = 37.5 kg·m/s + 5 kg·v2

387.5 kg·m/s = 5 kg·v2

Dividing both sides of the equation by 5 kg:

v2 = 387.5 kg·m/s / 5 kg

v2 = 77.5 m/s

Therefore, the velocity of the second body after the collision is 77.5 m/s.