Question

В вакууме, на расстоянии 15 см расположены два заряда 4*10−9 Кл и -6*10-8 Кл. Найдите силу, с которой взаимодействуют эти заряды. Нужно не только ответ, а ещё и решение. Помогите пожалуйста, у меня сейчас СОР! Даю 30 баллов!!! Подпишусь на того кто даст правильный и нормальный ответ.

Answer 1

Ответ: 0,96мкКл

Объяснение:

Дано:

q1=4*10⁻⁹Кл

q2=-6*10⁻⁸Кл

r=15cм=0,15м

--------------------

F-?

F=k * |q1q2| / r²= 9 * 10⁹ * (4 * 10⁻⁹ * 6 * 10⁻⁸) /0,15²=9,6*10⁻⁵ Н=0,96мкКл

Answer 2

Calculation of the Force between Two Charges

To find the force with which two charges interact in a vacuum, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:

F = k * (|q1 * q2|) / r^2

Where: - F is the force between the charges, - k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2), - q1 and q2 are the magnitudes of the charges, and - r is the distance between the charges.

In this case, we have two charges: q1 = 4 * 10^(-9) C and q2 = -6 * 10^(-8) C, with a distance of r = 15 cm = 0.15 m.

Let's calculate the force using the given values:

F = (9 * 10^9 Nm^2/C^2) * (|4 * 10^(-9) C * -6 * 10^(-8) C|) / (0.15 m)^2

Calculating the above expression will give us the force between the charges.

Calculation:

F = (9 * 10^9 Nm^2/C^2) * (4 * 10^(-9) C * 6 * 10^(-8) C) / (0.15 m)^2

F = (9 * 10^9 Nm^2/C^2) * (24 * 10^(-17) C^2) / (0.0225 m^2)

F = (9 * 24 * 10^(-8) N) / (0.0225)

F ≈ 96 N

Therefore, the force with which the two charges interact is approximately 96 Newtons.

Please note that the above calculation assumes that the charges are point charges and that the distance between them is much larger than their sizes.