Question

Найдите удлинение резиновой нити жесткостью 3,6 10³Н/м, если на неё действует сила 12кН​

Answer 1

Дано:                     Решение:

k = 3,6 10³Н/м       k = F/x

F = 12000 Н          x = F/k; х = 12000 Н/3,6 10³Н/м = 9,23 м

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х-?                               Ответ: 9,23 м

Answer 2

Finding the Elongation of a Rubber Thread

To find the elongation of a rubber thread with a stiffness of 3.6 * 10^3 N/m when a force of 12 kN is applied, we can use Hooke's Law, which states that the force needed to extend or compress a spring by some distance is proportional to that distance.

Using Hooke's Law to Calculate Elongation

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied (in newtons) - k is the stiffness of the material (in newtons per meter) - x is the elongation or compression of the material (in meters)

We can rearrange the formula to solve for x:

x = F / k

Calculating the Elongation

Substituting the given values: - F = 12 kN = 12,000 N - k = 3.6 * 10^3 N/m

We can calculate the elongation x:

x = 12,000 N / (3.6 * 10^3 N/m)

x ≈ 3.33 meters

Therefore, the elongation of the rubber thread under a force of 12 kN is approximately 3.33 meters.