Question

ПОМОГИТЕ ПЖ ДАЮ 100 БАЛЛОВ Малый поршень гидравлического пресса опустился на 25 см под действием силы 650 Н. Площадь малого поршня равна 3 см^2см , а площадь большого — 15 см^2см . Какая сила приложена на большой поршень и на какую высоту он переместился? Сила, приложенная к большому поршню, равна ... Н Большой поршень переместился на ...см.

Answer 1

Ответ: Сила приложенная к большому поршню, равна 3250 Н,
Большой поршень переместился на 5см

Объяснение:
F2/F1=S2/S1
F2/F1=15/3=5
F2=650*5=3250H

F2/F1=h1/h2
h1/h2=5
h2=25/5=5cм

Answer 2

Calculating Force and Displacement in a Hydraulic Press

To calculate the force applied to the large piston and the distance it moved, we can use the principles of Pascal's law, which states that in a closed system, a pressure change applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and to the walls of its container.

Given: - Small piston area (A1) = 3 cm^2 - Large piston area (A2) = 15 cm^2 - Force applied on the small piston (F1) = 650 N - Distance the small piston moved (d1) = 25 cm

Calculating the Force on the Large Piston

The force applied on the large piston (F2) can be calculated using the formula: F2 = F1 * (A2 / A1)

Substituting the given values: F2 = 650 N * (15 cm^2 / 3 cm^2) F2 = 650 N * 5 F2 = 3250 N

Therefore, the force applied to the large piston is 3250 N.

Calculating the Displacement of the Large Piston

The displacement of the large piston (d2) can be calculated using the formula: d2 = (A1 / A2) * d1

Substituting the given values: d2 = (3 cm^2 / 15 cm^2) * 25 cm d2 = (1/5) * 25 cm d2 = 5 cm

Therefore, the large piston moved a distance of 5 cm.

So, the force applied to the large piston is 3250 N and it moved a distance of 5 cm.