Question

Электрическая лампочка включена в сеть. Сила тока, протекающего через лампочку, равна 1,34 А. Чему равно сопротивление лампочки, если работа электрического тока в ней составляет 134,63 Дж? За время работы лампочки через поперечное сечение переносится заряд 14,4 Кл

Answer 1

Ответ:

Объяснение:

I = 1,34 А

A =  134,63 Дж

q =  14,4 Кл

R = ?

A = I^2*R*t

I = q/t        t = q/I

A = I^2*R*q / I = I*R*q

R = A / (I*q) = 134,63 / (1,34*14,4) == 7 Ом

Answer 2

Calculation of Resistance

To calculate the resistance of the light bulb, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I). In this case, the current is given as 1.34 A.

Ohm's Law: R = V / I

However, we are not given the voltage directly. Instead, we are given the work done by the electric current in the light bulb, which is 134.63 J. The work done by an electric current is equal to the product of the voltage and the charge (Q) that passes through the circuit.

Work done by electric current: W = V * Q

We are also given the charge that passes through the light bulb, which is 14.4 C.

Now, we can rearrange the equation for work done to solve for voltage (V):

V = W / Q

Substituting the given values:

V = 134.63 J / 14.4 C

Calculating the voltage:

V = 9.33 V

Now that we have the voltage and the current, we can calculate the resistance using Ohm's Law:

R = V / I

Substituting the values:

R = 9.33 V / 1.34 A

Calculating the resistance:

R ≈ 6.96 Ω

Therefore, the resistance of the light bulb is approximately 6.96 Ω.

Please note that the calculations are based on the given information and assumptions.