Question

скільки води можна нагріти від 10 °C до кіпіння за рахунок енергії,що виділяється під час ділення ядра урану-235?втратили енергії знехтувати.​

Answer 1

Відповідь: 8,5 ·10⁻¹⁷ кг

Пояснення:

Answer 2

Calculating the Energy Released by Uranium-235 Fission

To calculate the amount of water that can be heated from 10°C to boiling using the energy released by the fission of uranium-235, we need to determine the energy released by one fission event and then use this energy to calculate the amount of water that can be heated.

The energy released by the fission of uranium-235 is approximately 200 MeV (million electron volts) per fission event [[1]]. This energy can be converted to joules using the conversion factor 1 MeV = 1.60218 × 10^-13 joules [[2]].

Calculating the Amount of Water Heated

The specific heat capacity of water is 4.18 joules/gram°C [[3]]. To calculate the amount of water that can be heated from 10°C to boiling (100°C), we can use the following formula:

Q = mcΔT

Where: - Q = heat energy required (in joules) - m = mass of water (in grams) - c = specific heat capacity of water (in joules/gram°C) - ΔT = change in temperature (in °C)

Assuming we want to heat the water from 10°C to 100°C, the change in temperature (ΔT) is 90°C.

Calculation

Using the formula Q = mcΔT, we can calculate the mass of water that can be heated using the energy released by the fission of uranium-235.

Let's proceed with the calculation: - Energy released by one fission event = 200 MeV - Convert MeV to joules: 1 MeV = 1.60218 × 10^-13 joules - Specific heat capacity of water (c) = 4.18 joules/gram°C - Change in temperature (ΔT) = 90°C (from 10°C to 100°C)

We can now calculate the mass of water that can be heated using the energy released by the fission of uranium-235.