Question

Какое количество работы выполняется, когда наполненный мешок массой 10 кг падает с высоты 6 м? Коэффициент силы тяжести 9,8 H/KG ДАНО: m=...kg G=...n/kg s =..м Fтяж =? A=? При вычислении использую формулы: ... Ответ: на мешок действует сила тяжести Н, а при его падении выполняется работа Дж.

Answer 1

Ответ: 98Н; 588Дж

Объяснение:

ДАНО:

m=10kg

G=9.8n/kg

s =6м

----------------

Fтяж =?

A=?

Fтяж=mG=10*9.8=98Н

A=Fтяж*s=98*6=588Дж

Answer 2

Calculation of Work Done

To calculate the amount of work done when a bag with a mass of 10 kg falls from a height of 6 m, we can use the formula:

Work (W) = Force (F) × Distance (d) × cos(θ)

In this case, the force acting on the bag is the force of gravity, which can be calculated using the formula:

Force of Gravity (Fg) = mass (m) × acceleration due to gravity (g)

Given that the mass of the bag is 10 kg and the acceleration due to gravity is 9.8 m/s², we can calculate the force of gravity:

Fg = 10 kg × 9.8 m/s² = 98 N

The distance the bag falls is 6 m. Since the force of gravity acts vertically downward and the displacement is also vertical, the angle (θ) between the force and displacement is 0 degrees. Therefore, the cosine of 0 degrees is 1.

Using the formula for work, we can calculate the work done:

Work (W) = Fg × d × cos(θ) = 98 N × 6 m × cos(0°) = 588 J

Therefore, when the bag with a mass of 10 kg falls from a height of 6 m, the work done is 588 Joules (J).