Question

Вес легковой автомашины равен 12 кН. Площадь опоры каждого колеса равна 10 см2. Какое давление оказывает легковая автомашина на соответствующую поверхность? (При необходимости ответ округли до целого числа!) Давление равно кПа.

Answer 1

Ответ:300кПа

Объяснение:

Дано:

Р=12кН=12000Н

S1=10cм²=0,001м²

n=4

----------------------

р-?

р=Р/S=P/4S1=12000/(4*0,001)=300000Па=300кПа

Answer 2

Calculating Pressure Exerted by the Car

To calculate the pressure exerted by the car on the corresponding surface, we can use the formula:

Pressure (P) = Force (F) / Area (A)

Given: - Force (F) = 12 kN - Area (A) = 10 cm^2

Let's calculate the pressure using the given values.

Calculation

First, we need to convert the force from kilonewtons (kN) to newtons (N) as 1 kN = 1000 N.

So, the force F = 12 kN = 12,000 N.

Now, we can calculate the pressure using the formula:

Pressure (P) = Force (F) / Area (A)

Pressure (P) = 12,000 N / 10 cm^2

Converting the area from cm^2 to m^2: 1 cm^2 = 0.0001 m^2

So, the area A = 10 cm^2 = 0.001 m^2

Now, we can calculate the pressure:

Pressure (P) = 12,000 N / 0.001 m^2 = 12,000,000 Pa

Therefore, the pressure exerted by the car on the corresponding surface is 12,000,000 Pa.

Conclusion

The pressure exerted by the car on the corresponding surface is 12,000,000 Pa.