Question

С помощью пружины жёсткостью 96 Н/с брусок массой 2,4 равномерно тянут по столу. Определите удлинение пружины, если коэффициент трения между бруском и столом равен 0,2

Answer 1

Ответ:

Fтр=Fудл

μmg=kx ,где х это удлинение

0,2*2,4*10=96х

4,8=96х

х=4.8/96=5см

Ответ: 5 см

Answer 2

Calculation of Spring Elongation

To calculate the elongation of the spring, we can use the formula:

F = kx

Where: - F is the force applied to the spring - k is the spring constant (stiffness) in N/m - x is the elongation of the spring in meters

Given: - Spring constant, k = 96 N/m - Mass of the block, m = 2.4 kg - Coefficient of friction between the block and the table, μ = 0.2

Force Applied to the Spring

The force applied to the spring can be calculated using the formula:

F = mg

Where: - m is the mass of the block - g is the acceleration due to gravity (approximately 9.81 m/s^2)

Calculating the force applied to the spring: F = 2.4 kg * 9.81 m/s^2 F = 23.544 N

Elongation of the Spring

Now, we can calculate the elongation of the spring using the force applied and the spring constant:

F = kx x = F / k x = 23.544 N / 96 N/m x ≈ 0.245 m

Therefore, the elongation of the spring is approximately 0.245 meters.