
Воду массой 2 кг имеющую начальную температуру 25 градусов нагрели в электрическом чайнике до
кипения 100 градусов за 6 мин. Найти КПД чайника. Мощность электрического чайника 2кВт. Считать полученную работу идущую на нагревание воды.

Ответы на вопрос

Дано: Решение:
m= 25 кг ν=Aпол/Асов
T= 25 Aпол=cmT - работа, затраченная на нагревание воды
Tк=100 Асов=Pt - работа, затраченная на нагрев чайника
t=6 мин=360 с ν=cmT/Pt = 4200*2*75/2000*360=0.875=87.5%
P=2 кВт
Найти:
ν-?



Problem Analysis
We are given the following information: - Mass of water: 2 kg - Initial temperature of water: 25 degrees Celsius - Final temperature of water (boiling point): 100 degrees Celsius - Time taken to heat the water: 6 minutes - Power of the electric kettle: 2 kWWe need to find the efficiency (or thermal efficiency) of the electric kettle.
Solution
To find the efficiency of the electric kettle, we need to calculate the work done and the energy input.# Step 1: Calculate the energy input
The energy input can be calculated using the formula:Energy input = Power x Time
Given that the power of the electric kettle is 2 kW and the time taken to heat the water is 6 minutes, we can calculate the energy input as follows:
Energy input = 2 kW x 6 minutes
Note: We need to convert the time from minutes to seconds, as the power is given in kilowatts.
# Step 2: Calculate the work done
The work done can be calculated using the formula:Work done = Mass x Specific heat capacity x Change in temperature
The specific heat capacity of water is approximately 4.18 J/g°C.
Given that the mass of water is 2 kg, the initial temperature is 25 degrees Celsius, and the final temperature is 100 degrees Celsius, we can calculate the change in temperature as follows:
Change in temperature = Final temperature - Initial temperature
Now we can calculate the work done using the formula mentioned above.
# Step 3: Calculate the efficiency
The efficiency of the electric kettle can be calculated using the formula:Efficiency = (Work done / Energy input) x 100
Now we can substitute the values we calculated in the previous steps to find the efficiency.
Calculation
Let's calculate the efficiency of the electric kettle using the given information.# Step 1: Calculate the energy input
Energy input = 2 kW x 6 minutes = 12 kWh# Step 2: Calculate the work done
Change in temperature = 100°C - 25°C = 75°CWork done = 2 kg x 4.18 J/g°C x 75°C = 627 J
# Step 3: Calculate the efficiency
Efficiency = (Work done / Energy input) x 100 = (627 J / 12 kWh) x 100Note: We need to convert the energy input from kilowatt-hours (kWh) to joules (J) to have consistent units.
Answer
The efficiency of the electric kettle is approximately 0.005225%.Please note that the calculations provided are based on the given information and assumptions.


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