Question

Трактор массой 5,9т стоит на дороге.Соприкасающаяся с землёй часть его гусеницы имеет размеры 248см и 27см. Какое давление оказывает гусеничная опора трактора на землю? Принять g=10H/кг. Ответ округли до десятых трактор оказывает на землю p=... кПа

Answer 1

Ответ:

поменяй числы местами , и формулы всё сделают за тебя

Answer 2

Calculating Ground Pressure of the Tractor

To calculate the ground pressure exerted by the tractor, we can use the formula:

Ground Pressure (p) = Weight of Tractor (W) / Area of Contact

First, let's calculate the area of contact using the dimensions of the part of the track that touches the ground.

The area of contact can be calculated using the formula for the area of a rectangle:

Area = Length x Width

Given: - Weight of the tractor (W) = 5.9 tons = 5900 kg - Length of the track in contact with the ground = 248 cm = 2.48 m - Width of the track in contact with the ground = 27 cm = 0.27 m - Acceleration due to gravity (g) = 10 m/s^2

Now, let's calculate the area of contact and then use it to find the ground pressure.

Calculations

Area of Contact: Area = Length x Width Area = 2.48 m x 0.27 m Area = 0.6696 m^2

Ground Pressure: Ground Pressure (p) = Weight of Tractor (W) / Area of Contact Ground Pressure (p) = 5900 kg / 0.6696 m^2 Ground Pressure (p) ≈ 8810.4 kPa

So, the ground pressure exerted by the tractor on the ground is approximately 8810.4 kPa.