Question

Помогите пожалуйста, даю максимально кол-во баллов!! Определите, какое количество теплоты (в Дж) выделится на проводе из нихрома в течение 2 минут, если его длина 18 м, площадь поперечного сечения 0,5мм(2 в квадрате) и удельное сопротивление 110•10(-8 степени) Ом • м. Напряжение на концах нихромового провода равно 33 в.

Answer 1

Ответ: 3286,8Дж

Объяснение:

Дано:

t=2мин=120с

l=18м

S=0,5мм²

ρ=110*10⁻⁸ Ом*м=1,1 Ом*мм²/м

U=33В

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Q-?

Q=UIt

I=U/R

R=ρl/S=1,1*18/0,5=39,6 Ом

I=33/39,6=0,83А

Q=33*0,83*120=3286,8Дж

Answer 2

Calculation of Heat Released by the Nichrome Wire

To determine the amount of heat released by the nichrome wire, we can use the formula:

Q = I^2 * R * t

Where: - Q is the heat released (in Joules) - I is the current flowing through the wire (in Amperes) - R is the resistance of the wire (in Ohms) - t is the time for which the current flows (in seconds)

In this case, we are given the following information: - Length of the wire (L) = 18 m - Cross-sectional area of the wire (A) = 0.5 mm^2 - Specific resistance of nichrome wire (ρ) = 110 * 10^(-8) Ω•m - Voltage across the wire (V) = 33 V - Time (t) = 2 minutes = 120 seconds

To calculate the current flowing through the wire, we can use Ohm's Law:

V = I * R

Rearranging the equation, we get:

I = V / R

Let's calculate the current flowing through the wire:

I = V / R = 33 V / (110 * 10^(-8) Ω•m * 18 m) = 166666.67 A

Now, we can calculate the heat released by the wire using the formula mentioned earlier:

Q = I^2 * R * t = (166666.67 A)^2 * (110 * 10^(-8) Ω•m)