Question

Игральную кость бросают 600 раз. Какова вероятность того, что число выпадений шестерки будет между 86 и 114? Ответ не округлять.

Answer 1

Ответ:

Решение:

114+86=200

600/200=3

Ответ:3

Пошаговое объяснение:

Answer 2

Calculating the Probability

To calculate the probability of getting a number of sixes between 86 and 114 when rolling a die 600 times, we need to use the binomial probability formula. The binomial probability formula is given by:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where: - P(X = k) is the probability of getting exactly k successes (in this case, the number of times a six is rolled) - C(n, k) is the number of combinations of n items taken k at a time - p is the probability of success on a single trial (in this case, the probability of rolling a six) - n is the number of trials (in this case, the number of times the die is rolled) - k is the number of successes (in this case, the number of times a six is rolled)

In this case, we want to calculate the probability of getting a number of sixes between 86 and 114. So we need to calculate the probabilities for each value of k from 86 to 114 and sum them up.

Let's calculate the probability step by step:

1. Calculate the probability of rolling a six on a single trial: - Since a die has six sides and only one side has a six, the probability of rolling a six on a single trial is 1/6.

2. Calculate the number of combinations of 600 trials taken k at a time: - We can use the formula for combinations: C(n, k) = n! / (k! * (n-k)!) - In this case, n = 600 and k will vary from 86 to 114.

3. Calculate the probability of getting exactly k successes (rolling a six k times) in 600 trials: - Plug in the values into the binomial probability formula.

4. Sum up the probabilities for each value of k from 86 to 114 to get the final probability.

Let's calculate the probability using the given information.