Question

Самолёт пролетел расстояние за 1 ч 15 мин со скоростью 440 км/ч. С какой скоростью он летел обратно, если из-за плохой погоды потратил на 15 мин больше времени? (Ответ округлите до десятков, тема "прямая и обратная пропорциональная зависимость) с Решением пж

Answer 1

Ответ: 370км/ч
Решение: 15/60 =0,25ч
1+0,25=1,25ч
1,25*440=550км
550:(1,25+0,25)=366,666666…км/ч
366,6666…~370км/ч

Answer 2

Problem Analysis

We are given that a plane flew a certain distance in 1 hour and 15 minutes at a speed of 440 km/h. Due to bad weather, the plane took 15 minutes longer to return. We need to find the speed at which the plane flew back.

Solution

Let's start by calculating the time it took for the plane to fly the given distance. We know that the plane flew for 1 hour and 15 minutes, which is equivalent to 1.25 hours. We can use the formula:

Distance = Speed × Time

Substituting the given values, we have:

Distance = 440 km/h × 1.25 h

Now, let's calculate the distance traveled by the plane:

Distance = 550 km

Since the plane took 15 minutes longer to return, we can add 15 minutes to the total time it took to fly the distance. This gives us a total time of 1.25 hours + 0.25 hours = 1.5 hours.

Now, we can calculate the speed at which the plane flew back using the formula:

Speed = Distance / Time

Substituting the values, we have:

Speed = 550 km / 1.5 h

Calculating this, we find that the speed at which the plane flew back is approximately 367 km/h.

Answer

The plane flew back at a speed of approximately 367 km/h.