Question

Довжина прямокутника 10см а ширина -у 2 рази менша Знайди площу й периметр прямокутника

Answer 1

Покрокове пояснення:

1) 10÷2=5 (см)-ширина;

2) 5·10=50² (см)-площа;

3) 5·2+10·2=30(см)-периметр.

Answer 2

Ответ:

1) 10:2=5(см) - ширина прямокутника.

P=2•(10+5)=30(см) - периметр прямокутника.

S=10•5=50(см²) - площа прямокутника.

Відповідь: P=30cм, S=50см².

Answer 3

Calculation of the Area and Perimeter of a Rectangle

To find the area and perimeter of a rectangle, we need to know the length and width of the rectangle. In this case, the length of the rectangle is given as 10 cm, and the width is said to be 2 times smaller than the length.

Let's calculate the width of the rectangle first. Since the width is 2 times smaller than the length, we can divide the length by 2 to find the width:

Width = Length / 2 = 10 cm / 2 = 5 cm

Now that we have the length and width of the rectangle, we can calculate its area and perimeter.

Calculation of the Area of the Rectangle

The area of a rectangle is given by the formula:

Area = Length x Width

Substituting the given values:

Area = 10 cm x 5 cm = 50 cm²

Therefore, the area of the rectangle is 50 cm².

Calculation of the Perimeter of the Rectangle

The perimeter of a rectangle is given by the formula:

Perimeter = 2 x (Length + Width)

Substituting the given values:

**Perimeter = 2 x (10 cm + 5 cm) = 2 x 15 cm =