Question

Даны два различных числа x и y таковы, что x²-2000x=y²-2000y, Найдите x+y.​

Answer 1

Ответ:

$2000$

Пошаговое объяснение:

$x^{2} -2000x=y^{2} -2000y\\x^{2}- y^{2} =2000x-2000y\\(x-y)(x+y)=2000(x-y) /:(x-y)\\x+y=2000$

Answer 2

Problem Analysis

We are given two different numbers, x and y, such that x² - 2000x = y² - 2000y. We need to find the value of x + y.

Solution

To solve this problem, we can start by simplifying the equation x² - 2000x = y² - 2000y.

We can rewrite the equation as: x² - y² = 2000x - 2000y

Now, we can factor the left side of the equation using the difference of squares formula: (x - y)(x + y) = 2000(x - y)

Since x and y are different numbers, we can divide both sides of the equation by (x - y): x + y = 2000

Therefore, the value of x + y is 2000.

Answer: x + y = 2000