Question

Периметр параллелограмма равен 112 м. Найдите его стороны, если одна из них на 12 м меньше другой. Заранее спасибо.

Answer 1

Ответ:

Р ABCD=112м

РABCD=AB+BC+CD+AD

По свойству параллелограмма АВ=СD=x м, BC=AD=x+12 м.

Р ABCD=x+x+x+12+x+12=112

4x+24=112

4x=88

x=88:4

x=22 м

АВ=СD=22м

ВС=АD=22+12=34м

Answer 2

Problem Analysis

We are given that the perimeter of a parallelogram is 112 m. One of the sides is 12 m less than the other side. We need to find the lengths of the sides of the parallelogram.

Solution

Let's assume that one of the sides of the parallelogram is x m. According to the problem, the other side is 12 m more than x m. So, the length of the other side is x + 12 m.

The perimeter of a parallelogram is given by the formula: 2 * (side1 + side2).

Substituting the given values into the formula, we have: 2 * (x + (x + 12)) = 112

Simplifying the equation, we get: 2 * (2x + 12) = 112

Solving for x: 4x + 24 = 112 4x = 112 - 24 4x = 88 x = 88 / 4 x = 22

So, one side of the parallelogram is 22 m and the other side is 22 + 12 = 34 m.

Answer

The lengths of the sides of the parallelogram are 22 m and 34 m.