Question

А) 25-y²=(5-y)(5+y). б) a²-6ab+9b²=(a-3b)².

Answer 1

Ответ:

25-у²=(5-у)(5+у)

52-у²=25+5у-5у-у²- раскрываем скобки перемножая числа или можно применить правило

Разность квадратов двух чисел равна произведению разности этих чисел и их суммы.

a^2 - b^2 = (a - b)(a + b).

25-у²=25-у²

Пошаговое объяснение:

Answer 2

Equation A:

To solve the equation 25 - y² = (5 - y)(5 + y), we can start by simplifying the right side of the equation using the difference of squares formula, which states that a² - b² = (a - b)(a + b).

So, for equation A, we have:

25 - y² = (5 - y)(5 + y)

Using the difference of squares formula, we can rewrite the right side of the equation as:

25 - y² = (5 - y)(5 + y) = (5)² - y² = 25 - y²

Now, we have the equation:

25 - y² = 25 - y²

The equation is symmetric, which means that the left side and the right side are the same. This implies that the equation is true for all real values of y. So, the solution to equation A is all real numbers.

Equation B:

To solve the equation a² - 6ab + 9b² = (a - 3b)², we can use the square of a binomial formula, which states that (a - b)² = a² - 2ab + b².

So, for equation B, we have:

a² - 6ab + 9b² = (a - 3b)²

Using the square of a binomial formula, we can rewrite the right side of the equation as:

(a - 3b)² = a² - 2(a)(3b) + (3b)² = a² - 6ab + 9b²

Now, we have the equation:

a² - 6ab + 9b² = a² - 6ab + 9b²

The equation is symmetric, which means that the left side and the right side are the same. This implies that the equation is true for all real values of a and b. So, the solution to equation B is all real numbers for a and b.

In summary, the solutions to both equation A and equation B are all real numbers.